Question

Луч света падает на границу раздела двух сред под углом 32 градуса.абсолютный показатель преломления первой среды равен 2,4.каков абсолютный показатель преломления второй среды,если известно,что преломлённый луч перпендикулярен отражённому?

Answer 1

Решение: Мы знаем, что при переходе луча из одной среды в другую Sin α/sinβ=n2/n1 Так как падающий и преломленны лучи перпендикулярны, то угол преломления = 90-32=58 градусов. Теперь n2=n1*sinα/sinβ=1.5. Задача решена.

Answer 2

Calculation of the Absolute Refractive Index of the Second Medium

To calculate the absolute refractive index of the second medium, we can use Snell's law, which relates the angles of incidence and refraction to the refractive indices of the two media involved.

Snell's law is given by:

n1 * sin(i) = n2 * sin(r)

Where: - n1 is the refractive index of the first medium, - n2 is the refractive index of the second medium, - i is the angle of incidence, and - r is the angle of refraction.

In this case, we are given that the angle of incidence is 32 degrees, and the refractive index of the first medium is 2.4. We are also told that the refracted ray is perpendicular to the reflected ray.

Let's solve for the refractive index of the second medium using the given information.

Using the fact that the refracted ray is perpendicular to the reflected ray, we can deduce that the angle of refraction is 90 degrees. Therefore, sin(r) = 1.

Substituting the given values into Snell's law:

2.4 * sin(32) = n2 * 1

Simplifying the equation:

2.4 * sin(32) = n2

Now, we can calculate the refractive index of the second medium.

Using a scientific calculator, we find that sin(32) is approximately 0.5299.

Substituting this value into the equation:

2.4 * 0.5299 = n2

Calculating the result:

n2 ≈ 1.2718

Therefore, the absolute refractive index of the second medium is approximately 1.2718.

Please note that the calculation is based on the given information and the assumption that the refracted ray is perpendicular to the reflected ray.