Question

При никелировании пластины в процессе электролиза толщина слоя никеля увеличивается с постонной скоростью дельта h /дельта t =0,045 мм/ч .определите силу тока в цепи ,если площадь поверхности детали S=2.5*10 в степени 2 см2.Электрохимический эквивалент никеля K=0.30*10 в 5 степени кг/Кл.плотностью никеля p=8.6*10 в 3 степени кг/м3

Answer 1

У меня в тетрадке записано , что R=r значит внутреннее сопротивление равно 30 Ом, а дальше не знаю(1) R = R1+R2R=6 Ом+24Ом=30 Ом

Answer 2

Calculation of Current in the Circuit during Electroplating

To determine the current in the circuit during electroplating, we can use the formula:

I = (m * K) / (ρ * S * Δt)

Where: - I is the current in the circuit (in Amperes) - m is the mass of the deposited material (in kilograms) - K is the electrochemical equivalent of the material (in kg/Coulomb) - ρ is the density of the material (in kg/m^3) - S is the surface area of the part (in m^2) - Δt is the time interval (in seconds)

In this case, we are given the following values: - Δh/Δt = 0.045 mm/h = 0.045 * 10^-3 m/h - S = 2.5 * 10^2 cm^2 = 2.5 * 10^-2 m^2 - K = 0.30 * 10^5 kg/Coulomb - ρ = 8.6 * 10^3 kg/m^3

To calculate the current, we need to convert the given values to the appropriate units and substitute them into the formula.

Converting the given values: - Δh/Δt = 0.045 * 10^-3 m/h = (0.045 * 10^-3 m/h) * (1 h / 3600 s) = 1.25 * 10^-8 m/s

Substituting the values into the formula: I = (m * K) / (ρ * S * Δt) I = (m * 0.30 * 10^5 kg/Coulomb) / (8.6 * 10^3 kg/m^3 * 2.5 * 10^-2 m^2 * 1.25 * 10^-8 m/s)

Simplifying the equation: I = (m * 0.30 * 10^5) / (8.6 * 2.5 * 1.25) * 10^3 A

Therefore, the current in the circuit during electroplating is given by the equation: I = (m * 0.30 * 10^5) / (21.25) * 10^3 A

Please provide the mass of the deposited material (in kilograms) to calculate the current accurately.