Question

Определите модуль силы, которую необходимо приложить в горизонтальном направлении к телу массой 1 кг,неподвижно лежащему на горизонтальной поверхности , чтобы оно через промежуток времени 2 с приобрело скорость модуль которой 2 м/с.Извесно, что модуль силы сопротивления при жвижении тела F= 3Н ОООООЧЕНЬ СРОЧНО!!!!!

Answer 1

M=1 кг   t=2 c    Fc=3 H    F=?
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F-Fc=m*a
a=v/t    (vo=0)
F=m*v/t+Fc=1*2/2+3=4 H
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Answer 2

Calculation of the Force Required

To determine the force required to accelerate a stationary object with a mass of 1 kg to a velocity of 2 m/s in a time interval of 2 seconds, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, the object is initially at rest, so its initial velocity is 0 m/s. The final velocity is given as 2 m/s, and the time interval is 2 seconds. We can calculate the acceleration using the formula:

acceleration = (final velocity - initial velocity) / time interval

Substituting the given values, we have:

acceleration = (2 m/s - 0 m/s) / 2 s = 1 m/s^2

Now, we can calculate the force required using the formula:

force = mass * acceleration

Substituting the mass of 1 kg and the acceleration of 1 m/s^2, we have:

force = 1 kg * 1 m/s^2 = 1 N

Therefore, the force required to accelerate the 1 kg object to a velocity of 2 m/s in 2 seconds is 1 Newton.

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