Question

Перемещаясь равномерно,ученик массой 40 кг поднял на 2-й этаж школьного здания,находящегося на высоте 3 м,груз массой 10кг.Перемещаясь равномерно,другой ученик массой45 кг поднял на эту же высоту груз массой 8 кг. Кто из них проделал совершил большую работу

Answer 1

m1=40кг+10кг

m2=45кг+8кг

 S=3м

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найти А2-А1

 

 

А= F*S

найдём работу первого ученика

 

F1= m*g=(40кг+10кг)*10м/с.кв=500Н

А1= 500Н* 3м=1500Дж

 

найдём работу второго ученика

 

F2= m*g=(45кг+8кг)*10м/с.кв=530Н

А1= 530Н* 3м=1590Дж

1590Дж - 1500Дж = 90Дж

второй ученик совершил рабору больше на 90 Дж

Answer 2

Calculation of Work Done by Each Student

To determine which student performed more work, we need to calculate the work done by each student. The work done is given by the formula:

Work = Force × Distance

For the first student: - Mass of the student (m1) = 40 kg - Mass of the load (m1_load) = 10 kg - Height (h1) = 3 m

For the second student: - Mass of the student (m2) = 45 kg - Mass of the load (m2_load) = 8 kg - Height (h2) = 3 m

Let's calculate the work done by each student.

Work Done by the First Student

The force exerted by the first student can be calculated using Newton's second law:

Force = mass × acceleration

Since the student is moving uniformly, the acceleration is zero. Therefore, the force exerted by the student is equal to the weight of the load.

The weight of an object can be calculated using the formula:

Weight = mass × acceleration due to gravity

Acceleration due to gravity (g) is approximately 9.8 m/s^2.

Let's calculate the force exerted by the first student:

Force1 = m1_load × g

Now, we can calculate the work done by the first student:

Work1 = Force1 × h1

Work Done by the Second Student

Similar to the first student, the force exerted by the second student is equal to the weight of the load:

Force2 = m2_load × g

Now, we can calculate the work done by the second student:

Work2 = Force2 × h2

Comparing the Work Done

To determine which student performed more work, we can compare the values of Work1 and Work2. The student who has a higher value of work done has performed more work.

Let's calculate the work done by each student and compare the results.

Calculation

Using the given values and the formulas mentioned above, we can calculate the work done by each student:

For the first student: - Force1 = 10 kg × 9.8 m/s^2 = 98 N - Work1 = 98 N × 3 m = 294 J

For the second student: - Force2 = 8 kg × 9.8 m/s^2 = 78.4 N - Work2 = 78.4 N × 3 m = 235.2 J

Answer

Therefore, the first student performed more work, with a value of 294 J, compared to the second student, who performed 235.2 J of work.