Question

При подходе к станции поезд уменьшил скорость на 10м/с в течении 20с. С каким ускорением двигался поезд?

Answer 1

v = v0 - a*t v0 - v = a * t, отсюда a = (v0 - v) / t (где (v0 - v) как раз и есть 10м/с). тогда a = 1/2 м/(с^2)

Answer 2

Calculation of Acceleration

To calculate the acceleration of the train, we need to use the formula:

Acceleration (a) = Change in Velocity (Δv) / Time (t)

Given that the train reduces its speed by 10 m/s over a period of 20 seconds, we can substitute these values into the formula:

Acceleration (a) = -10 m/s / 20 s

The negative sign indicates that the train is decelerating or slowing down.

Now let's calculate the acceleration:

Acceleration (a) = -0.5 m/s² Therefore, the train is decelerating with an acceleration of -0.5 m/s².

Please let me know if there's anything else I can help you with!