Question

Капельками ртути массой 20г каждая, находящимися на стекле на расстоянии 4,0см одна от другой, сообщили заряды -6,0*10^-8 и 2,0*10^-7 Кулон. В какую сторону и с каким ускорением они начнут двигаться? Будет ли при этом движение равноускоренным? Силы гравитации не учитывайте. Решите пожалуйста очень срочно)

Answer 1

Вычислим, по закону Кулона, силу притяжения капелек.
F=k*q1*q2 / r^2.
F=9*10^9*6*10^(-8)*2*10^(-7) / 0,0016=0,0675Н. Так как силы взаимодействия одинаковы по модулю, по 2 закону Ньютона, вычислим ускорения.
a1=F / m1.
a2=F / m2.
a1=0,0675 / 0,02=3,375м/c^2. так как массы одинаковы
а1=а2.

Answer 2

Problem Analysis

We are given two mercury droplets with masses of 20g each, located on a glass surface at a distance of 4.0cm from each other. The charges on the droplets are -6.0*10^-8 C and 2.0*10^-7 C. We need to determine the direction and acceleration with which the droplets will start moving. We also need to determine if the motion will be uniformly accelerated. The force of gravity can be ignored in this problem.

Solution

To solve this problem, we can use Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for the force between two charges is given by:

F = k * (q1 * q2) / r^2

Where: - F is the force between the charges, - k is the electrostatic constant (9 * 10^9 N m^2/C^2), - q1 and q2 are the charges on the droplets, and - r is the distance between the droplets.

Let's calculate the force between the droplets using the given values:

F = (9 * 10^9 N m^2/C^2) * ((-6.0 * 10^-8 C) * (2.0 * 10^-7 C)) / (0.04 m)^2

Calculating this expression, we find that the force between the droplets is approximately -0.675 N.

Since the charges on the droplets have opposite signs, the force between them is attractive. Therefore, the droplets will move towards each other.

To determine the acceleration with which the droplets will start moving, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.

The formula for acceleration is given by:

a = F / m

Where: - a is the acceleration, - F is the net force acting on the droplets, and - m is the mass of each droplet.

Substituting the values, we have:

a = (-0.675 N) / (0.02 kg)

Calculating this expression, we find that the acceleration of the droplets is approximately -33.75 m/s^2.

The negative sign indicates that the acceleration is in the opposite direction to the initial motion of the droplets.

Since the acceleration is constant, the motion of the droplets will be uniformly accelerated.

Therefore, the droplets will start moving towards each other with an acceleration of approximately -33.75 m/s^2.

Conclusion

The droplets will start moving towards each other with an acceleration of approximately -33.75 m/s^2. The motion will be uniformly accelerated.