Question

Определите давление керосина на дно цистерны , если уровень керосина в цистерне 2 метра. Плотность керосина 800кг/м3

Answer 1

P=ρgh
ρ=800 кг/м3
g=10 Н/кг
h=2 м
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p=800*10*2=16000 Па=16 кПа
Ответ: 16 кПа

Answer 2

По формуле давления:
р=po*g*h. ( p-давление, ро - плотность жидкости (керосина=800кг/куб. м.) , h-высота столба=2м, g -ускорение свободного падения=10м/c^2).
р=800*10*2=16000Па. (16кПа).

Answer 3

Calculation of Pressure

To determine the pressure of kerosene at the bottom of the tank, we can use the formula:

Pressure (P) = density (ρ) × gravitational acceleration (g) × height (h)

Given that the density of kerosene is 800 kg/m³ and the height of the kerosene in the tank is 2 meters, we can substitute these values into the formula to calculate the pressure.

Density (ρ) = 800 kg/m³ Height (h) = 2 meters

Using the formula, we can calculate the pressure:

Pressure (P) = ρ × g × h

Substituting the values:

Pressure (P) = 800 kg/m³ × 10 m/s² × 2 m

Calculating the expression:

Pressure (P) = 16000 N/m²

Therefore, the pressure of the kerosene at the bottom of the tank is 16000 N/m² or 16 kPa (kilopascals).

Please note that the above calculation assumes standard gravity (9.81 m/s²) and does not take into account any additional factors such as atmospheric pressure or temperature.