Question

Частота колебаний маятника 10 Гц. Чему равен период колебаний маятника? Какой путь он пройдёт за период колебвний, если амплитуда колебаний 4см? Решите пожалуйста и если не сложно с формулами

Answer 1

период равен 1/частоту!!!!  у тебя получается 1/10=0,1с   путь равен 4/0,1=40м

Answer 2

T=1/v=0.1 с

S=2A=0.04*2=0.08 м

Answer 3

Frequency and Period of Oscillations

The frequency of a pendulum's oscillations is given by the formula:

Frequency (f) = 1 / Period (T)

In this case, the frequency of the pendulum is given as 10 Hz. To find the period, we can rearrange the formula:

Period (T) = 1 / Frequency (f)

Substituting the given frequency of 10 Hz into the formula, we can calculate the period:

Period (T) = 1 / 10 Hz = 0.1 seconds [[1]].

Therefore, the period of the pendulum's oscillations is 0.1 seconds.

Distance Traveled in One Period

The distance traveled by a pendulum in one complete period can be calculated using the formula:

Distance (d) = 2 * π * Amplitude (A)

In this case, the amplitude of the pendulum's oscillations is given as 4 cm. Substituting this value into the formula, we can calculate the distance traveled in one period:

Distance (d) = 2 * π * 4 cm = 8π cm [[2]].

Therefore, the pendulum will travel a distance of 8π cm in one period of oscillation.

I hope this helps! Let me know if you have any further questions.