Question

Имея скорость 20 м/с поезд начинает тормозить так, что движется с ускорением 0,1 м/с^2 в течении 50с . какой станет скорость поезда по окончании торможения?

Answer 1

V0=20 м/c
a=0,1 м/c^2
t=50c
_________
v - ?                             v = v - at - формула для скорости, когда тело                                                                  тормозит.
                                    v = 20*50 - 0,1*50 = 95м /c.

Answer 2

Calculation of the Final Velocity of the Train

To calculate the final velocity of the train after braking, we can use the following equation of motion:

v = u + at

Where: - v is the final velocity - u is the initial velocity - a is the acceleration - t is the time

In this case, the initial velocity (u) of the train is 20 m/s, the acceleration (a) is -0.1 m/s^2 (negative because it is deceleration), and the time (t) is 50 s.

Substituting these values into the equation, we can calculate the final velocity (v):

v = 20 + (-0.1) * 50

Calculating this expression, we find:

v = 20 - 5

Therefore, the final velocity of the train after braking will be 15 m/s.

Please note that the above calculation assumes that the train maintains a constant deceleration of 0.1 m/s^2 throughout the entire braking process.