Question

Три шаровидных капли ртути,равный по обьему и имеющие электрические заряды q1=10(-4) Кл,q2=-2*10(-4)Кл и q3=4*10(-4)Кл,сливаются в одну.какой электрический заряд будет иметь образовавшиаяся капля и с какой силой она будет взаимодействовать с другими электрическим зарядом q4=10(-9) Кл,находящимися в воздухе на расстоянии 50 см от неё"

Answer 1

Заряды складываются арифметически
q=q1+q2+q3=10(-4) Кл -2*10(-4)Кл + 4*10(-4)Кл =3*10(-4)Кл
F=k*q*q4/r^2=8,99*10^9*3*10^(-4)*10^(-9)/(0,5)^2 H = 0,010788 H ~ 0,01 H

Answer 2

Calculation of the Electric Charge of the Merged Mercury Droplet

To determine the electric charge of the merged mercury droplet, we need to consider the conservation of electric charge. According to the principle of conservation of charge, the total electric charge before and after the merging of the droplets should remain the same.

Given the electric charges of the three individual droplets as follows: - q1 = 10^(-4) C - q2 = -2 * 10^(-4) C - q3 = 4 * 10^(-4) C

To find the total electric charge after merging, we can simply add the charges of the individual droplets:

q_total = q1 + q2 + q3

Let's calculate the value of q_total:

q_total = 10^(-4) C + (-2 * 10^(-4)) C + 4 * 10^(-4) C

q_total = 2 * 10^(-4) C

Therefore, the electric charge of the merged mercury droplet is 2 * 10^(-4) C.

Interaction Force between the Merged Droplet and the Electric Charge in Air

To calculate the interaction force between the merged droplet and the electric charge q4 = 10^(-9) C in the air, we can use Coulomb's law. Coulomb's law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:

F = k * (|q1| * |q2|) / r^2

Where: - F is the force between the charges - k is the electrostatic constant (approximately equal to 9 * 10^9 Nm^2/C^2) - q1 and q2 are the magnitudes of the charges - r is the distance between the charges

In this case, the magnitude of the charge of the merged droplet is |q_total| = 2 * 10^(-4) C, and the magnitude of the charge in the air is |q4| = 10^(-9) C. The distance between them is 50 cm, which is equal to 0.5 m.

Let's calculate the interaction force using Coulomb's law:

F = (9 * 10^9 Nm^2/C^2) * ((2 * 10^(-4) C) * (10^(-9) C)) / (0.5 m)^2

F = (9 * 10^9 Nm^2/C^2) * (2 * 10^(-13) C^2) / (0.25 m^2)

F = 18 * 10^(-4) N

Therefore, the interaction force between the merged droplet and the electric charge in the air is 18 * 10^(-4) N.