
У подножия горы барометр показывает 760мм.рт.ст. Определите давление на вершине, если её высота
2,7км. Пожалуйста решите, очень срочно!

Ответы на вопрос

при подъеме на высоту 2 700 метров давление уменьшится на
2700/12 = 225 мм. рт. ст.
Значит, давление на вершине горы:
p = 760 - 225 = 535 мм.рт.ст.



Calculating Pressure Difference from Base to Summit of a Mountain
To calculate the pressure difference from the base to the summit of a mountain, we can use the formula for the relationship between pressure and altitude in the Earth's atmosphere. The formula is given by:
P = P₀ * e^(-Mgh/RT)
Where: - P is the pressure at the given altitude - P₀ is the pressure at sea level - M is the molar mass of Earth's air - g is the acceleration due to gravity - h is the height above sea level - R is the ideal gas constant - T is the temperature in Kelvin
Calculation Steps
1. First, we need to convert the given barometric pressure from mmHg to atm, as the formula requires pressure to be in atmospheres. 2. Then, we can use the given height of the mountain to calculate the pressure at its summit.
Conversion from mmHg to atm
The conversion factor from mmHg to atm is 1 atm = 760 mmHg. Therefore, to convert 760 mmHg to atm: 760 mmHg * (1 atm / 760 mmHg) = 1 atmSo, the pressure at the base of the mountain is 1 atm.
Calculating Pressure at the Summit
Given: - Height of the mountain, h = 2.7 km - Acceleration due to gravity, g = 9.81 m/s² - Molar mass of air, M = 0.029 kg/mol - Ideal gas constant, R = 8.314 J/(mol·K) - Standard temperature at sea level, T = 288 KUsing the formula P = P₀ * e^(-Mgh/RT), we can calculate the pressure at the summit of the mountain.
Calculation
P = 1 atm * e^(-0.029 kg/mol * 9.81 m/s² * 2700 m / (8.314 J/(mol·K) * 288 K))Calculating this expression gives us the pressure at the summit of the mountain.
I hope this helps! If you have any further questions or need additional assistance, feel free to ask.


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