Question

В горячую воду массой 2 кг при температуре 90 градусов С опускают исследуемую деталь массой 900 г с начальной температурой 12 градусов. После установления теплового равновесия температура системы достигла 83 градуса. Вычислите удельную теплоемкость детали, если удельная теплоемкость воды равно 4200 Дж/кг гр. цельсия

Answer 1

4200*2*(90-83)= с*0,900*(83-12)
58 800 = 63,9*с
с=58800/63,9 = 920 Дж/(кг*°С)

Похоже, что деталь АЛЮМИНИЕВАЯ

Answer 2

Calculating Specific Heat Capacity of the Object

To calculate the specific heat capacity of the object, we can use the formula:

Q = mcΔT

Where: - Q = heat absorbed or released - m = mass - c = specific heat capacity - ΔT = change in temperature

Given: - Mass of water, m1 = 2 kg - Initial temperature of water, T1 = 90°C - Mass of the object, m2 = 900 g = 0.9 kg - Initial temperature of the object, T2 = 12°C - Final temperature of the system, Tf = 83°C - Specific heat capacity of water, c1 = 4200 J/kg°C

First, let's calculate the heat absorbed by the water and the object separately.

The heat absorbed by the water can be calculated using the formula: Q1 = m1c1ΔT1

Where: - Q1 = heat absorbed by water - m1 = mass of water - c1 = specific heat capacity of water - ΔT1 = change in temperature of water

The heat absorbed by the object can be calculated using the formula: Q2 = m2c2ΔT2

Where: - Q2 = heat absorbed by the object - m2 = mass of the object - c2 = specific heat capacity of the object - ΔT2 = change in temperature of the object

Then, we can use the fact that the total heat absorbed by the water and the object is equal to zero: Q1 + Q2 = 0

We can solve for the specific heat capacity of the object, c2, using the above information.

Let's proceed with the calculations.