Question

Для нагревания стальной детали от 20°С? до 70°С затратили 460кДЖ теплоты.Какова масса детали?(с=460дж/кг К)

Answer 1

M=q: (c(t-t0))
m=460:(460×(70-20)=0.02кг

Answer 2

Q = mc(t2 - t1)
m=Q/c(t2-t1) = 460000/460*50 = 20кг

Answer 3

Calculating the Mass of the Steel Part

To calculate the mass of the steel part, we can use the formula:

Q = mcΔT

Where: - Q = heat energy (in joules) - m = mass (in kilograms) - c = specific heat capacity (in joules per kilogram per degree Celsius) - ΔT = change in temperature (in degrees Celsius)

Given: - Initial temperature (T1) = 20°C - Final temperature (T2) = 70°C - Heat energy (Q) = 460 kJ = 460,000 J - Specific heat capacity (c) = 460 J/kg°C

We can rearrange the formula to solve for the mass (m):

m = Q / (c * ΔT)

Calculation

Substitute the given values into the formula:

m = 460,000 J / (460 J/kg°C * (70°C - 20°C))

m = 460,000 J / (460 J/kg°C * 50°C)

m = 460,000 J / 23,000 J/kg

m = 20 kg

Answer

The mass of the steel part is 20 kg.