Question

Какова индукция магнитного поля,в котором на проводник с длиной активной части 6см действует сила 60 мН?Сила тока в проводнике 20А(проводник расположен перпендикулярно индукции магнитного поля.)

Answer 1

Ну раз перпендикулярно, то
В=F/LI=(60*10^-3)/20*6*10^-2=1/20 Тл

Answer 2

Calculating the Magnetic Field Induction

To calculate the induction of the magnetic field in which a conductor with an active length of 6 cm is subjected to a force of 60 mN with a current of 20 A flowing through it, we can use the formula for the force on a current-carrying conductor in a magnetic field:

F = B * I * l * sin(θ)

Where: - F is the force on the conductor (60 mN or 0.06 N) - B is the magnetic field induction - I is the current (20 A) - l is the length of the conductor (6 cm or 0.06 m) - θ is the angle between the direction of the current and the magnetic field (90 degrees as the conductor is perpendicular to the magnetic field)

We can rearrange the formula to solve for B:

B = F / (I * l * sin(θ))

Substitute the given values into the formula to find the magnetic field induction:

B = 0.06 N / (20 A * 0.06 m * sin(90°))

B = 0.06 N / (1.2 T)

B ≈ 0.05 T

So, the induction of the magnetic field in which the conductor is placed is approximately 0.05 T.