Question

В цепь последовательно включены резисторы сопротивлением 14, 20 и 48 Ом. Какое напряжение будет показывать вольтметр на каждом резисторе, если сила тока равна 0,25 А ?

Answer 1

U1=I*R1   U1=0.25 A*14 Ом=3.5 B

U2=I*R2   U2=0.25 A*20 Ом=5 В

U3=I*R3   U3=0.25 A*48 Ом=12 В

При последовательном соединении сила тока в цепи на всез резисторах одинаковая,а напряжение разное

Answer 2

Calculating Voltage Across Resistors in a Series Circuit

To calculate the voltage across each resistor in a series circuit, we can use Ohm's law, which states that voltage (V) is equal to the current (I) multiplied by the resistance (R), or V = I * R.

Given: - Resistance of the first resistor (R1) = 14 Ω - Resistance of the second resistor (R2) = 20 Ω - Resistance of the third resistor (R3) = 48 Ω - Current (I) = 0.25 A

Calculating Voltage Across Each Resistor

1. Voltage across the first resistor (V1): - Using Ohm's law: V1 = I * R1 - Substituting the given values: V1 = 0.25 A * 14 Ω - Calculating V1: V1 = 3.5 V 2. Voltage across the second resistor (V2): - Using Ohm's law: V2 = I * R2 - Substituting the given values: V2 = 0.25 A * 20 Ω - Calculating V2: V2 = 5 V 3. Voltage across the third resistor (V3): - Using Ohm's law: V3 = I * R3 - Substituting the given values: V3 = 0.25 A * 48 Ω - Calculating V3: V3 = 12 V

Summary

The voltage across each resistor in the series circuit with resistances of 14 Ω, 20 Ω, and 48 Ω, and a current of 0.25 A, is as follows: - Voltage across the first resistor (V1): 3.5 V - Voltage across the second resistor (V2): 5 V - Voltage across the third resistor (V3): 12 V