Question

Из орудия массой вылетает снаряд массой 20 кг со скоростью 700 м/c. Найти силу давления пороховых газов,считая ее постоянной, считая ее постоянной во все время движения снаряда 0,01 с в стволе орудия. Полное Решение.

Answer 1

Дано
m=20кг
v=700м/с
t=0,01c
найти
F
решение
L-длина ствола
средняя скорость движения снаряда в стволе Vcp=v/2
L=t*Vcp=vt/2
кинетическая энергия снаряда равна работе силы давление пороховых газов
Ek=A
mv^2/2=F*L
mv^2/2=F*vt/2
F=mv/t=20*700/0.01=1400000 H =1400 кН =1.4 МН
ответ 
=1400 кН
=1.4 МН

Answer 2

Problem Analysis

We are given the mass of a projectile and its velocity, and we need to find the force exerted by the propellant gases assuming it is constant throughout the projectile's motion.

Solution

To find the force exerted by the propellant gases, we can use Newton's second law of motion, which states that the force acting on an object is equal to the rate of change of its momentum. Mathematically, this can be expressed as:

F = Δp / Δt

where F is the force, Δp is the change in momentum, and Δt is the change in time.

The momentum of an object is given by the product of its mass and velocity:

p = m * v

where p is the momentum, m is the mass, and v is the velocity.

Since the mass of the projectile remains constant, we can rewrite the equation as:

F = m * Δv / Δt

where Δv is the change in velocity.

To find the change in velocity, we can use the equation of motion:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the initial velocity (u) is 0 m/s, as the projectile starts from rest. The final velocity (v) is given as 700 m/s. The time (t) is given as 0.01 s.

We can rearrange the equation of motion to solve for acceleration:

a = (v - u) / t

Substituting the given values, we can find the acceleration.

Finally, we can substitute the values of mass (20 kg) and acceleration into the equation for force to find the force exerted by the propellant gases.

Let's calculate the force step by step.

Calculation

Given: - Mass of the projectile (m) = 20 kg - Initial velocity (u) = 0 m/s - Final velocity (v) = 700 m/s - Time (t) = 0.01 s

1. Calculate the acceleration (a): - a = (v - u) / t - a = (700 - 0) / 0.01 - a = 70000 m/s^2

2. Calculate the force (F): - F = m * a - F = 20 kg * 70000 m/s^2 - F = 1400000 N

Answer

The force exerted by the propellant gases is 1400000 N.