Question

Поезд прошёл от станции расстояние 1,5 км. За это время он развил скорость 54 км/ч. Определить ускорение и время разгона поезда

Answer 1

Дано:
$S=1,5_K_M=1500_M\\ \nu=54 \frac{_K_M}{4} =15 \frac{_M}{_C}\\ \nu_0=0\\ -----\\ a; t-?$

Решение:
$S= \frac{\nu^2-\nu_0^2}{2a}= \frac{\nu^2}{2a}\Rightarrow a= \frac{\nu^2}{2S} \\ a= \frac{15^2}{2*1500}=0,075 \frac{_M}{c^2} \\ S= \frac{at^2}{2}\Rightarrow t= \sqrt{ \frac{2S}{a}}\\ t= \sqrt{\frac{2*1500}{0,075} } =200c$

Answer 2

Given Data

The train traveled a distance of 1.5 km and reached a speed of 54 km/h.

Calculating Acceleration

To calculate the acceleration of the train, we can use the formula: Acceleration = (Final Speed - Initial Speed) / Time

Given: - Initial Speed (u) = 0 km/h (assuming the train starts from rest) - Final Speed (v) = 54 km/h - Distance (s) = 1.5 km

We can calculate the time taken to reach the final speed using the formula: Time = Distance / Speed

Using the given data, we can calculate the acceleration and the time taken for the train to reach its final speed.

Calculations

Time Taken: Time = Distance / Speed Time = 1.5 km / 54 km/h Time = 0.02778 hours

Acceleration: Acceleration = (Final Speed - Initial Speed) / Time Acceleration = (54 km/h - 0 km/h) / 0.02778 hours Acceleration = 1944 km/h^2

Results

- Time Taken: 0.02778 hours - Acceleration: 1944 km/h^2

So, the train took approximately 0.02778 hours to reach a speed of 54 km/h, and its acceleration was approximately 1944 km/h^2.