Question

Определить среднюю кинетическую энергию молекулы одноатомного газа и концентрацию молекул при температуре 290 К и давлении 0,8 МПа

Answer 1

k=1.38*10^-23     T=290    p=0.8*10^6

<E>=(3/2)k*T=........... Дж

n=(3/2)*(p/<E>)=......

Answer 2

Calculation of Average Kinetic Energy of a Molecule of a Monoatomic Gas

To calculate the average kinetic energy of a molecule of a monoatomic gas, we can use the formula:

E = (3/2)kT

Where: - E is the average kinetic energy of a molecule - k is the Boltzmann constant (1.38 x 10^-23 J/K) - T is the temperature in Kelvin

Given that the temperature is 290 K, we can substitute the values into the formula:

E = (3/2) * (1.38 x 10^-23 J/K) * 290 K

Calculating this expression will give us the average kinetic energy of a molecule of the monoatomic gas at the given temperature.

Calculation of Concentration of Molecules

To calculate the concentration of molecules, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure in Pascal (Pa) - V is the volume in cubic meters (m^3) - n is the number of moles of gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature in Kelvin

Given that the pressure is 0.8 MPa (0.8 x 10^6 Pa) and the temperature is 290 K, we can rearrange the equation to solve for the number of moles (n):

n = PV / RT

Substituting the values into the equation will give us the number of moles of gas. Since we are dealing with a monoatomic gas, the number of moles will also be equal to the number of molecules.

To calculate the concentration, we need to divide the number of moles by the volume of the gas. However, the volume is not provided in the question. Therefore, we cannot calculate the concentration without the volume information.

Please provide the volume of the gas so that we can calculate the concentration.