
Людина масою 50 кг стрибає на пліт масою 400 кг у напрямку перпендикулярному до його руху .
Визначте швидкість плота разом з людиною якщо горизонтальна швидкість людини перед стрибком 1,2 м/c а швидкість плота 0,2м/с.

Ответы на вопрос




Calculation of the Speed of the Boat with the Person
To determine the speed of the boat with the person, we can use the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.
The momentum of an object is calculated by multiplying its mass by its velocity. In this case, we have a person with a mass of 50 kg and a horizontal velocity of 1.2 m/s, and a boat with a mass of 400 kg and a velocity of 0.2 m/s.
Before the jump, the momentum of the person is given by:
Momentum of the person before the jump = mass of the person × velocity of the person
Momentum of the person before the jump = 50 kg × 1.2 m/s
After the jump, the momentum of the person and the boat together is given by:
Momentum of the person and the boat after the jump = (mass of the person + mass of the boat) × velocity of the boat with the person
Momentum of the person and the boat after the jump = (50 kg + 400 kg) × velocity of the boat with the person
According to the principle of conservation of momentum, the momentum before the jump is equal to the momentum after the jump. Therefore, we can set up the following equation:
50 kg × 1.2 m/s = (50 kg + 400 kg) × velocity of the boat with the person
To find the velocity of the boat with the person, we can rearrange the equation:
Velocity of the boat with the person = (50 kg × 1.2 m/s) / (50 kg + 400 kg)
Now, let's calculate the velocity of the boat with the person using the given values:
Velocity of the boat with the person = (50 kg × 1.2 m/s) / (50 kg + 400 kg)
Velocity of the boat with the person = (60 kg·m/s) / 450 kg
Velocity of the boat with the person ≈ 0.133 m/s
Therefore, the speed of the boat with the person is approximately 0.133 m/s.


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