Question

с какой силой выталкивается киросином кусок стекла объемом 10 см3

Answer 1

F=pgV=10*10^(-5)*800=0,08 н

Answer 2

Выталкивающая сила равна весу жидкости в объеме тела, погруженного в жидкость.

Fa=gp(ж)Vт    g = 10 Н/кг, p(ж) =плотность жидкости, в данном случае плотность речной воды= 1000 кг/м3,  

Vт=объем тела = 10 см3=0,00001м3

Fa= 10Н/кг х 1000 кг/м3 х 0,00002 м3= 0,1H

Answer 3

Calculating the Force Exerted by Kerosene on a Glass

To calculate the force exerted by kerosene on a glass, we can use the formula for pressure, which is force per unit area. The formula for pressure is:

Pressure = Force / Area

Given: - Volume of kerosene = 10 cm^3 - Density of kerosene = 0.8 g/cm^3 - Acceleration due to gravity = 9.8 m/s^2 - Area of the glass in contact with kerosene = Assume the glass is in the shape of a cube with sides of length 1 cm (for simplicity)

Calculating the Force:

First, we need to calculate the mass of the kerosene using the formula:

Mass = Volume x Density

Substitute the given values: Mass = 10 cm^3 x 0.8 g/cm^3

Now, convert the mass from grams to kilograms: Mass = 10 cm^3 x 0.8 g/cm^3 x 0.001 kg/g

Next, we can calculate the force exerted by the kerosene on the glass using the formula:

Force = Mass x Acceleration due to gravity

Substitute the calculated mass and the given acceleration due to gravity: Force = (10 cm^3 x 0.8 g/cm^3 x 0.001 kg/g) x 9.8 m/s^2

Now, we can calculate the force.

Result:

The force exerted by the kerosene on the glass can be calculated using the above steps.