Question

Камень бросили вертикально вверх со скоростью 30 м/с .путь который тело пройдёт за 4 секунды после начала своего движения равен??

Answer 1

не слушай его(выше) 

h=v^2/2g=45м

t=v0/g=3cек

4-3=1сек падения

10*1=10м

45+10=55м

Answer 2

30 * 4 = 120м Скорость умнажаем на время и получаем путь)

Answer 3

Calculation of the Distance Traveled by the Object

To calculate the distance traveled by the object, we can use the formula for the vertical motion of a projectile:

Δy = v0t + (1/2)gt^2

Where: - Δy is the vertical displacement or distance traveled - v0 is the initial velocity (30 m/s in this case) - t is the time (4 seconds in this case) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Plugging in the values, we can calculate the distance traveled:

Δy = (30 m/s)(4 s) + (1/2)(9.8 m/s^2)(4 s)^2

Simplifying the equation:

Δy = 120 m + (1/2)(9.8 m/s^2)(16 s^2)

Δy = 120 m + (1/2)(9.8 m/s^2)(256 s^2)

Δy = 120 m + 1254.4 m

Δy = 1374.4 m

Therefore, the distance traveled by the object in 4 seconds after the start of its motion is approximately 1374.4 meters.