Question

Найдите длину нити маятника, на котором колеблется груз массой 100г, если за 10 сек совершается 20 полных колебаний

Answer 1

T/n=2*пи* корень квадратный из (l/g)
t^2/n^2=4*пи^2*l/g
t^2**g/n^2=4*пи*l
l=t^2*g/4*пи*n^2=10*10*10/4*3.14*3.14*20*20=1000/4*10*400=0.0625(м)=6,25(см)

Answer 2

Calculating the Length of the Pendulum Thread

To calculate the length of the pendulum thread on which a mass of 100g oscillates for 20 complete oscillations in 10 seconds, we can use the formula for the period of a pendulum:

Period of a Pendulum (T) = 2π√(L/g)

Where: - T = period of the pendulum - L = length of the pendulum - g = acceleration due to gravity (approximately 9.81 m/s²)

We can rearrange the formula to solve for L:

L = (T² * g) / (4π²)

Given that the pendulum completes 20 oscillations in 10 seconds, we can find the period (T) and then use it to calculate the length (L) of the pendulum thread.

Calculation

First, let's calculate the period (T) of the pendulum: T = Total time / Number of oscillations T = 10 s / 20 oscillations T = 0.5 s

Now, we can use the period (T) to calculate the length (L) of the pendulum thread: L = (T² * g) / (4π²) L = (0.5 s)² * 9.81 m/s² / (4 * π²) L ≈ 0.123 m

So, the length of the pendulum thread on which the mass oscillates is approximately 0.123 meters.