Question

Найти объем ,водорода масса 21кг температура 27градусов и плотность 100кПа

Answer 1

решение: воспользуемся уравнением Клапейрона-Менделеева

pV=RTm/Mr

 теперь выводим из этого уравнения объем получаем такую формулу:
V=mRT/Mr*p

и подставляем 

Mr(H2)=2*10 в минус 3 степени

V=21*8.31*300/2*10 в - 3 степени * 100000=2,6*10 в 3 степени

ответ: V(H2)=2.6 * 10 в 3 степени 

 

Answer 2

Calculating the Volume of Hydrogen

To calculate the volume of hydrogen, we can use the ideal gas law formula, which is given by:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

Given: - Mass of hydrogen (m) = 21 kg - Temperature (T) = 27 degrees Celsius - Density (ρ) = 100 kPa

First, we need to calculate the number of moles of hydrogen using the mass and molar mass of hydrogen.

Calculating the Number of Moles of Hydrogen

The molar mass of hydrogen (H2) is approximately 2 g/mol.

Using the formula: moles = mass / molar mass

We can calculate the number of moles of hydrogen: moles = 21000 g / 2 g/mol = 10500 moles

Calculating the Volume of Hydrogen

Now, we can use the ideal gas law to calculate the volume of hydrogen.

Given: - Temperature (T) = 27 degrees Celsius = 300 K (Kelvin) (adding 273.15 to convert Celsius to Kelvin) - Density (ρ) = 100 kPa = 100000 Pa (converting kPa to Pa)

Using the ideal gas law formula: PV = nRT

We can rearrange the formula to solve for V (volume): V = (nRT) / P

Substituting the values: V = (10500 moles * 8.314 J/(mol*K) * 300 K) / 100000 Pa

Calculating the volume: V ≈ 249.42 m^3

So, the volume of hydrogen at a mass of 21 kg, temperature of 27 degrees Celsius, and density of 100 kPa is approximately 249.42 cubic meters.