Question

На пружине жёсткостью 50 Н/м висит груз, при этом длина пружины составляет 12 см. Определите массу груза, если в недеформированном состоянии длина пружины равна 10 см 1

Answer 1

F=kx
F=ma
kx=ma
50*0.02=m*10
m=0.1 кг

Answer 2

Calculation of the Mass of the Load Hanging on a Spring

To determine the mass of the load hanging on a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

The formula for Hooke's Law is:

F = k * x

Where: - F is the force exerted by the spring, - k is the spring constant (also known as the stiffness constant), - x is the displacement of the spring from its equilibrium position.

In this case, we are given that the spring constant is 50 N/m and the length of the spring in its undeformed state is 10 cm.

To find the mass of the load, we need to convert the displacement of the spring from centimeters to meters. So, the displacement (x) is equal to the difference between the initial length of the spring (10 cm) and the final length of the spring (12 cm), converted to meters:

x = (12 cm - 10 cm) / 100 = 0.02 m

Now, we can use Hooke's Law to find the force exerted by the spring:

F = k * x = 50 N/m * 0.02 m = 1 N

According to Newton's second law of motion, the force exerted by the spring is equal to the weight of the load hanging on the spring:

F = m * g

Where: - m is the mass of the load, - g is the acceleration due to gravity (approximately 9.8 m/s^2).

Rearranging the equation, we can solve for the mass of the load:

m = F / g = 1 N / 9.8 m/s^2 ≈ 0.102 kg

Therefore, the mass of the load hanging on the spring is approximately 0.102 kg.

Answer:

The mass of the load hanging on the spring is approximately 0.102 kg.