Question

При подходе к светофору водитель автобуса уменьшил скорость на пути 40 м в 1,5 раза за 4 с. Определите ускорение, считая его постоянным.

Answer 1

Скороcть V=V0-at
учтем, что скорость уменьшилась в 1, 5 раза
V0/1.5=v0-at  выразим V0
v0=-3at
и подставим в формулу для перемещения
$S=V0t+ \frac{at^2}{2}$
получим
40=3а*4-a*16/2
40=12a-8a
40=4a отсюда a=10м/c^2

Answer 2

Calculation of Acceleration

To determine the acceleration of the bus, we need to use the formula:

Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)

In this case, the driver of the bus reduced the speed by a factor of 1.5 in a distance of 40 m over a time of 4 s.

The change in velocity (Δv) can be calculated by subtracting the final velocity from the initial velocity. Since the initial velocity is not given, we can assume it to be the speed of the bus before the reduction.

Let's assume the initial speed of the bus is v.

The final velocity can be calculated by multiplying the initial velocity (v) by the reduction factor of 1.5:

Final velocity = v * 1.5

The change in velocity (Δv) is then:

Δv = Final velocity - Initial velocity

The time taken (Δt) is given as 4 s.

Now, we can substitute the values into the formula to calculate the acceleration:

Acceleration (a) = Δv / Δt

Let's calculate the acceleration step by step.

1. Calculate the final velocity: - Final velocity = v * 1.5

2. Calculate the change in velocity: - Δv = Final velocity - Initial velocity

3. Calculate the acceleration: - Acceleration (a) = Δv / Δt

Please note that we don't have the exact values for the initial velocity and the final velocity, so we will calculate the acceleration in terms of v.

Let's proceed with the calculation.