Question

На какую высоту можно было бы поднять груз массой 10 кг, если бы удалось полностью использовать энергию, освобождающуюся при остывании 1 литр воды от 20 градусов цельсия до 20 градусов цельсия удельная теплоемкость воды 4200 джоулей а плотность воды 1000 кг на метр в кубе

Answer 1

Mв=p*V=1000*1/1000=1 кг
Q=c*m*dt=4200*1*20=84000 Дж
Q=m1*g*h
h=Q/m1*g=84000/10*10=840 м

Answer 2

Calculating the Height to Which a 10kg Mass Could Be Lifted Using the Energy Released by Cooling 1 Liter of Water

To calculate the height to which a 10kg mass could be lifted using the energy released by cooling 1 liter of water from 20 degrees Celsius to 20 degrees Celsius, we can use the formula:

Potential energy = mass * gravity * height

The energy released by cooling 1 liter of water can be calculated using the formula:

Energy = mass * specific heat capacity * temperature change

Given: - Mass of water (m) = 1 kg (since the density of water is 1000 kg/m^3) - Specific heat capacity of water (c) = 4200 J/kg°C - Temperature change (ΔT) = 0°C (cooling from 20°C to 20°C)

We can calculate the energy released by cooling 1 liter of water: Energy = m * c * ΔT

Substituting the given values: Energy = 1 kg * 4200 J/kg°C * 0°C = 0 J

This means that no energy is released by cooling the water from 20°C to 20°C, so the potential energy available to lift the 10kg mass is zero.

Therefore, the height to which a 10kg mass could be lifted using the energy released by cooling 1 liter of water from 20 degrees Celsius to 20 degrees Celsius is zero.