Question

Какова должна быть наименьшая вместимость баллона, что бы он вмещал 6,4 кг кислорода при 20градусах цельсия, если его стенки выдерживают давление 16МПа

Answer 1

20 л так как 6,4 умножите на 20 градусов

Answer 2

Calculating the Minimum Capacity of the Cylinder

To calculate the minimum capacity of the cylinder required to hold 6.4 kg of oxygen at 20 degrees Celsius and withstand a pressure of 16 MPa, we can use the ideal gas law formula:

V = (nRT) / P

Where: - V = volume of the cylinder - n = number of moles of gas - R = ideal gas constant - T = temperature in Kelvin - P = pressure

First, we need to calculate the number of moles of oxygen using the given mass and the molar mass of oxygen.

The molar mass of oxygen (O2) is approximately 32 g/mol.

n = m / M

Where: - n = number of moles - m = mass - M = molar mass

n = 6.4 kg / 32 g/mol = 200 moles

Now, we convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15 T(K) = 20°C + 273.15 = 293.15 K

Now we can calculate the volume using the ideal gas law formula:

V = (nRT) / P V = (200 * 8.314 * 293.15) / 16000000 V ≈ 0.966 m^3

So, the minimum capacity of the cylinder should be approximately 0.966 cubic meters to hold 6.4 kg of oxygen at 20 degrees Celsius and withstand a pressure of 16 MPa.