Question

Падение молота массой 5 кг продолжалось 0.5 с определите потенциальную энергию молота относительно наковальни в начале падения и кинетическую энергию в момент падения.Какой энергией обладало тело,находясь высоте 1 метр

Answer 1

Eп=mgh=5×10×1=50Дж
v=h/t=2 м/сек
Eк=mv^2/2=5×4÷2=10Дж
Eоб=Eп+Eк=50+10=60Дж

Answer 2

Calculation of Potential Energy:

To calculate the potential energy of the hammer at the beginning of its fall, we can use the formula:

Potential Energy = mass * acceleration due to gravity * height

Given: - Mass of the hammer (m) = 5 kg - Acceleration due to gravity (g) = 9.8 m/s^2 - Height (h) = 1 meter

Using the formula, we can calculate the potential energy:

Potential Energy = 5 kg * 9.8 m/s^2 * 1 meter

Calculating the above expression, we find that the potential energy of the hammer at the beginning of its fall is 49 Joules.

Calculation of Kinetic Energy:

To calculate the kinetic energy of the hammer at the moment of impact, we can use the formula:

Kinetic Energy = (1/2) * mass * velocity^2

Given: - Mass of the hammer (m) = 5 kg - Velocity (v) = unknown

Unfortunately, the velocity of the hammer at the moment of impact is not provided in the question. Without this information, we cannot calculate the exact kinetic energy of the hammer at the moment of impact.

Energy of the Object at a Height of 1 Meter:

To determine the energy possessed by an object at a height of 1 meter, we need to consider both the potential energy and the kinetic energy.

At the beginning, when the object is at a height of 1 meter, it possesses potential energy. As it falls, this potential energy is converted into kinetic energy. At the moment of impact, all the potential energy is converted into kinetic energy.

Therefore, at a height of 1 meter, the object possesses only potential energy, which is equal to 49 Joules.

Please note that without the velocity of the hammer at the moment of impact, we cannot determine the exact kinetic energy at that moment.