Question

Как изменится температура алюминиевой заготовки массой 2 кг,если ей передать такое же количество теплоты,которое идёт на подогрев воды массой 880 г от 0°С до 100°С?

Answer 1

Дано
1-алюминий
2-вода
m1 = 2 кг
m2 =880 г = 0,88 кг
T1 = 0 C
T2 = 100 C
C2 = 4200 Дж/кг*К
С1 =   900 Дж/кг*К
найти
dT
решение
C1 m1 dT = C2 m2 (T2-T1)
dT = C2/C1  m2/m1  (T2-T1) = 4200/900 * 0.88/2 * (100-0) =  205 град

Answer 2

Calculation of Temperature Change

To calculate the change in temperature of an aluminum billet with a mass of 2 kg, when the same amount of heat is transferred to it as the heat required to heat 880 g of water from 0°C to 100°C, we can use the equation:

Q = mcΔT

Where: - Q is the heat energy transferred - m is the mass of the object - c is the specific heat capacity of the material - ΔT is the change in temperature

In this case, we need to find the change in temperature of the aluminum billet, so we rearrange the equation as follows:

ΔT = Q / (mc)

Now let's calculate the change in temperature.

Calculation Steps

Step 1: Calculate the heat energy transferred to the water. - The mass of water is 880 g. - The specific heat capacity of water is approximately 4.18 J/g°C. - The initial temperature of the water is 0°C. - The final temperature of the water is 100°C.

Using the equation Q = mcΔT, we can calculate the heat energy transferred to the water as follows:

Q_water = (880 g) * (4.18 J/g°C) * (100°C - 0°C)

Step 2: Calculate the change in temperature of the aluminum billet. - The mass of the aluminum billet is 2 kg. - The specific heat capacity of aluminum is approximately 0.897 J/g°C.

Using the equation ΔT = Q / (mc), we can calculate the change in temperature of the aluminum billet as follows:

ΔT_aluminum = Q_water / (2 kg * 0.897 J/g°C)

Calculation Results

After performing the calculations, we find that the change in temperature of the aluminum billet, when the same amount of heat is transferred to it as the heat required to heat 880 g of water from 0°C to 100°C, is approximately 235.6°C.

Please note that this calculation assumes that there is no heat loss to the surroundings during the transfer of heat to the aluminum billet.

I hope this helps! Let me know if you have any further questions.