Question

С помощью рычага поднимают груз весом 600 Н на высоту 0,1 м, действуя силой 160 Н. Точка приложения этой силы опустилась на 0,4 м. Определите КПД рычага.

Answer 1

Полезная энергия = 600*100 = 60000 джоулей.
Затраченная энергия = 350*1.8 = 630 джоулуй.
КПД = 60000/630 = 95.24

Answer 2

Calculation of Efficiency (КПД) of the Lever

To determine the efficiency (КПД) of the lever, we need to calculate the work input and work output.

Given: - Force applied (F) = 160 N - Distance moved by the point of application (d1) = 0.4 m - Weight of the load (W) = 600 N - Height lifted (h) = 0.1 m

Calculation:

The work input (W_input) is given by the product of the applied force and the distance moved by the point of application:

W_input = F * d1

Substituting the given values:

W_input = 160 N * 0.4 m

The work output (W_output) is given by the product of the weight of the load and the height lifted:

W_output = W * h

Substituting the given values:

W_output = 600 N * 0.1 m

The efficiency (КПД) of the lever is given by the ratio of the work output to the work input, multiplied by 100%:

Efficiency (КПД) = (W_output / W_input) * 100%

Substituting the calculated values:

Efficiency (КПД) = (600 N * 0.1 m) / (160 N * 0.4 m) * 100%

Simplifying the expression:

Efficiency (КПД) = 0.375 * 100%

Therefore, the efficiency (КПД) of the lever is 37.5%.