Question

Пружина жесткостью 10 Н/м растянута на 5 см, какую работу совершит сила упругости при её растяжении ещё на 5 см?

Answer 1

Первоначальная энергия:
A₁ = k*x² / 2 

Конечная энергия:
A₂ = k*(2*x)² / 2  = 4*k*x² / 2

Работа силы упругости:
A = A₂-A₁ = 3*k*x²/2 = 3*10*(0,05)²/2 = 0,0375 Дж

Answer 2

Calculation of Work Done by the Spring

To calculate the work done by the spring when it is stretched by an additional 5 cm, we can use the formula for the work done by a spring, which is given by:

W = (1/2)kx^2

Where: - W is the work done - k is the spring constant - x is the displacement from the equilibrium position

Given: - Spring constant, k = 10 N/m - Initial displacement, x1 = 5 cm = 0.05 m - Additional displacement, x2 = 5 cm = 0.05 m

Using the formula, we can calculate the work done by the spring when it is stretched by an additional 5 cm.

W1 = (1/2) * 10 * (0.05)^2 Now, to find the work done when the spring is stretched by an additional 5 cm, we can use the total displacement x = x1 + x2.

W2 = (1/2) * 10 * (0.1)^2

By subtracting the initial work from the total work, we can find the work done by the spring when it is stretched by an additional 5 cm.

Work done by the spring when stretched by an additional 5 cm = W2 - W1

Calculating the values will give us the specific work done by the spring when stretched by an additional 5 cm.