Question

Рассчитайте давление атмосферы в шахте глубиной 360 метра если на поверхности Земли давление 750 миллиметров ртутного столба

Answer 1

При снижении на каждые 12 метров давление увеличивается на 1мм.рт.ст.
Узнаем, на сколько мм.рт.ст. изменилось давление:
360м:12м =30мм.рт.ст.
На поверхности давление 750мм.рт.ст. , в шахте оно на 30мм.рт.ст. больше
750мм.рт.ст.+30мм.рт.ст. =780мм.рт.ст.

Answer 2

Calculating Atmospheric Pressure in a 360-Meter-Deep Mine Shaft

To calculate the atmospheric pressure in a mine shaft 360 meters deep, we can use the formula for hydrostatic pressure, which is given by the equation:

P = ρgh

Where: - P = pressure - ρ = density of the fluid - g = acceleration due to gravity - h = height of the fluid column

Given that the pressure at the surface of the Earth is 750 millimeters of mercury (mmHg), we can use this information to calculate the pressure at a depth of 360 meters in the mine shaft.

Calculation

First, we need to convert the pressure at the surface from millimeters of mercury to pascals, as the SI unit of pressure is the pascal (Pa). 1 mmHg is equal to 133.322387415 pascals.

So, 750 mmHg is equal to: 750 mmHg * 133.322387415 Pa/mmHg = 99991.76561125 Pa

Now, we can calculate the pressure at a depth of 360 meters using the formula for hydrostatic pressure.

Given: - ρ (density of mercury) = 13,595 kg/m³ - g (acceleration due to gravity) = 9.81 m/s² - h (height) = 360 meters

Using the formula: P = ρgh P = 13,595 kg/m³ * 9.81 m/s² * 360 m = 47,231,748 Pa

Therefore, the atmospheric pressure in a mine shaft 360 meters deep is approximately 47,231,748 pascals.

Conclusion

The atmospheric pressure in a mine shaft 360 meters deep is approximately 47,231,748 pascals.