Question

Шарик массой 0,1 кг движется по окружности x2 + y2 =0,25 со скоростью 2 м/с. Какая сила действует на шарик?

Answer 1

F=m*a
a=V^2/R
R=0.5
F=0.1*2^2/0.5=0.8 H

Answer 2

Calculation of the Force Acting on the Ball

To determine the force acting on the ball, we need to consider the centripetal force acting towards the center of the circular path. The centripetal force is given by the equation:

F = (m * v^2) / r

Where: - F is the centripetal force - m is the mass of the ball (0.1 kg) - v is the velocity of the ball (2 m/s) - r is the radius of the circular path

Given that the equation of the circular path is x^2 + y^2 = 0.25, we can express x in terms of y as x = sqrt(0.25 - y^2).

To find the radius of the circular path, we can differentiate the equation of the circular path with respect to y and solve for dy/dx:

2x * dx/dy + 2y = 0

Simplifying the equation, we have:

dx/dy = -y / x

Substituting the expression for x, we get:

dx/dy = -y / sqrt(0.25 - y^2)

Integrating both sides with respect to y, we can find the value of x in terms of y:

x = -sqrt(0.25 - y^2) + C

To find the value of C, we can substitute the coordinates of a point on the circular path. Let's choose the point (0, 0.5):

0 = -sqrt(0.25 - (0.5)^2) + C

Solving for C, we find C = sqrt(0.25 - (0.5)^2).

Therefore, the equation of the circular path is:

x = -sqrt(0.25 - y^2) + sqrt(0.25 - (0.5)^2)

Now we can substitute this equation into the centripetal force equation to calculate the force acting on the ball.