Question

Чему равна энергия магнитного поля катушки индуктивностью 2 Гн при силе тока в ней 3 А?

Answer 1

W= LI^2 / 2
W= 2*9/ 2= 9 дж

Answer 2

Calculating the Energy of a Magnetic Field in a Coil

To calculate the energy of a magnetic field in a coil with an inductance of 2 H and a current of 3 A, we can use the formula for the energy stored in an inductor:

Energy = (1/2) * L * I^2

Where: - L is the inductance in henrys (H) - I is the current in amperes (A)

Calculation

Using the given values: - Inductance (L) = 2 H - Current (I) = 3 A

We can calculate the energy as follows:

Energy = (1/2) * 2 H * (3 A)^2

Energy = (1/2) * 2 H * 9 A^2

Energy = 9 J

So, the energy of the magnetic field in the coil with an inductance of 2 H and a current of 3 A is 9 joules.