Question

Автомобиль массой 5 т движется равномерно по прямой горизонтальной дороге. Коэффициент трения шин о дорогу равен 0,03. Определите силу тяги развиваемую двигателем.

Answer 1

Силу трения находим из формулы: Fтр.=μFнорм., то есть Fтр.=0.03*50000=1500 Н, следовательно, для того, что бы двигатель заставил автомобиль ехать с такой силой трения ему нужна тяга, равная 51500 Н.

Answer 2

Calculation of the Tractive Force

To determine the tractive force developed by the engine, we need to consider the frictional force acting on the car. The frictional force is given by the equation:

Frictional force = coefficient of friction * normal force

The normal force is equal to the weight of the car, which can be calculated using the formula:

Weight = mass * gravitational acceleration

Given that the mass of the car is 5 tons (or 5000 kg) and the coefficient of friction between the tires and the road is 0.03, we can calculate the tractive force as follows:

Step 1: Calculate the weight of the car:

Weight = mass * gravitational acceleration

Weight = 5000 kg * 9.8 m/s^2

Weight = 49000 N

Step 2: Calculate the frictional force:

Frictional force = coefficient of friction * normal force

Frictional force = 0.03 * 49000 N

Frictional force = 1470 N

Therefore, the tractive force developed by the engine is 1470 N.