Question

Известно что на прямолинейный проводник длиной 10 см, находящийся в однородном магнитном поле, действует максимальная сила, модуль которой равен 1,5 * 10степени -2 H. Чему равен модуль вектора магнитной индукции, если сила тока в проводнике равна 3А? ПЛИЗ ПОМОГИТЕ 50 БАЛОВ ДАЮ ПОЖ СРОЧНО

Answer 1

ΔL=10 cм=0,1 м             B=F/ΔL*I
F=1,5 10⁻² H                   B=1,5 10⁻²/0,1*3=5 10⁻² Tл
I=3 A                               Ответ: В=5 10⁻² Тл.
B-?

Answer 2

Проводник находится перпендикулярно линия магнитной индукции.

Answer 3

Calculation of Magnetic Induction

To calculate the magnitude of the magnetic induction (also known as magnetic field strength or magnetic flux density), we can use the formula:

B = (F / (I * L))

Where: - B is the magnitude of the magnetic induction (in teslas, T) - F is the maximum force acting on the conductor (in newtons, N) - I is the current flowing through the conductor (in amperes, A) - L is the length of the conductor (in meters, m)

In this case, we are given that the maximum force acting on the conductor is 1.5 * 10^-2 H (H is the symbol for henries, not the unit for magnetic field strength). The length of the conductor is 10 cm, which is equal to 0.1 m. The current flowing through the conductor is 3 A.

Substituting these values into the formula, we get:

B = (1.5 * 10^-2 H) / (3 A * 0.1 m)

Simplifying the expression, we find:

B = 0.05 T

Therefore, the magnitude of the magnetic induction is 0.05 teslas.

Please note that the given search results did not provide any relevant information for this specific calculation. However, the formula used is a well-known equation in electromagnetism.