Question

Металлический брусок массой 125 г совершает колебания на пружине жесткостью 50H/м. Чему равен период колебания бруска?

Answer 1

T=2*pi*корень кв(m/k)=6,28*корень(0,125/50)=0,314с

Answer 2

Calculation of the Period of Oscillation

To calculate the period of oscillation for a mass-spring system, we can use the formula:

T = 2π√(m/k)

where: - T is the period of oscillation, - m is the mass of the object, - k is the spring constant.

In this case, the mass of the metal block is given as 125 g (or 0.125 kg), and the spring constant is given as 50 H/m.

Substituting these values into the formula, we can calculate the period of oscillation:

T = 2π√(0.125/50)

Let's calculate this:

T = 2π√(0.125/50) ≈ 0.282 seconds

Therefore, the period of oscillation for the metal block is approximately 0.282 seconds.