Question

Сколько джоулей тепла выделится при остывании 9 см³ никеля на 27 ºС? Плотность никеля 8,9 г/см³. Удельная теплоёмкость никеля 460 Дж/(кг׺С).

Answer 1

Оу,так это ж элементарно )

Q=C*m*Δt
m=pV    ⇒   Q=C*pV*Δt = 460*8.9*9*27
Вам осталось только посчитать)

Answer 2

Calculation of Heat Released during Cooling of Nickel

To calculate the amount of heat released during the cooling of nickel, we need to use the formula:

Q = m * c * ΔT

Where: - Q is the heat released (in joules) - m is the mass of the nickel (in kilograms) - c is the specific heat capacity of nickel (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

Given information: - Volume of nickel: 9 cm³ - Density of nickel: 8.9 g/cm³ - Specific heat capacity of nickel: 460 J/(kg׺C) - Change in temperature: 27 ºC

To calculate the mass of the nickel, we can use the density formula:

Density = mass / volume

Rearranging the formula, we get:

mass = density * volume

Let's calculate the mass of the nickel first:

mass = 8.9 g/cm³ * 9 cm³

Converting grams to kilograms:

mass = (8.9 g/cm³ * 9 cm³) / 1000 g/kg

Now, we can calculate the heat released using the formula mentioned earlier:

Q = mass * c * ΔT

Substituting the values:

Q = (mass) * 460 J/(kg׺C) * 27 ºC

Let's calculate the mass of the nickel:

mass = (8.9 g/cm³ * 9 cm³) / 1000 g/kg = 0.0801 kg

Now, we can calculate the heat released:

Q = (0.0801 kg) * 460 J/(kg׺C) * 27 ºC

Calculating the value:

Q = 0.0801 kg * 460 J/(kg׺C) * 27 ºC = 1,000.78 J

Therefore, approximately 1,000.78 joules of heat will be released during the cooling of 9 cm³ of nickel by 27 ºC.