Question

Период вращения винта самолета 0,6 с. сколько составляет линейная скорость самых крайних точек винта если диаметр винта 1м?

Answer 1

За один оборот крайняя точка винта проходит путь L = 2*π*R = 2*3,14*1 м = 6,28 м.
Этот пут точка проходит за 0,6 с.
Найдем линейную скорость
v = L / T = 6,28 м / 0,6 с = 10,5 м/с

Answer 2

Calculation of Linear Velocity of the Outermost Points of an Airplane Propeller

To calculate the linear velocity of the outermost points of an airplane propeller, we need to know the rotational speed of the propeller and the diameter of the propeller.

Given: - Period of rotation of the propeller: 0.6 s - Diameter of the propeller: 1 m

To find the linear velocity, we can use the formula:

Linear Velocity = 2 * π * Radius / Time Period

Since the diameter is given, we can calculate the radius by dividing the diameter by 2:

Radius = Diameter / 2

Substituting the values into the formula, we get:

Linear Velocity = 2 * π * (Diameter / 2) / Time Period

Now, let's calculate the linear velocity.

Calculation:

Given: - Time Period (T) = 0.6 s - Diameter (D) = 1 m

Radius (R) = Diameter / 2 = 1 m / 2 = 0.5 m

Linear Velocity = 2 * π * Radius / Time Period

Substituting the values:

Linear Velocity = 2 * π * 0.5 m / 0.6 s

Using the value of π as approximately 3.14159, we can calculate the linear velocity:

Linear Velocity ≈ 2 * 3.14159 * 0.5 m / 0.6 s

Linear Velocity ≈ 3.14159 * 0.5 m / 0.6 s

Linear Velocity ≈ 1.5708 m / 0.6 s

Linear Velocity ≈ 2.618 m/s

Therefore, the linear velocity of the outermost points of the airplane propeller is approximately 2.618 m/s.

Please note that the above calculation assumes a uniform rotation of the propeller and does not take into account any other factors that may affect the actual linear velocity of the outermost points of the propeller.

Conclusion:

The linear velocity of the outermost points of the airplane propeller, with a diameter of 1 m and a rotational period of 0.6 s, is approximately 2.618 m/s.