Question

Определите силу, под действием которой велосепедист скатывается с горки с ускорением равным 0,8 м/с2 если масса велосепедиста вместе с велосипедом равна 50 кг

Answer 1

Дано:
a=0,8 м/с2
m= 50 кг
Найти
F
Решение:
По 2 закону Ньютона
F=ma=50*0,8= 40H
Ответ 40H

Answer 2

A=0,8м/с2 m=50кг F=m*a F=50*0,8=40H

Answer 3

Calculation of the Force

To determine the force acting on the cyclist as they roll down a hill with an acceleration of 0.8 m/s^2, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the cyclist and the bicycle is given as 50 kg, and the acceleration is 0.8 m/s^2.

Using the formula F = ma, we can calculate the force:

F = (50 kg) * (0.8 m/s^2) = 40 N.

Therefore, the force acting on the cyclist is 40 Newtons.