
Помогите) чему равен ток если 2 литра воды, взятой при. 10 С закипает за 17 минут? кпд чайника 86%
. напряжение 220В. определиь сопротивления спирали

Ответы на вопрос

c=4200 m=po*V=1000*0.002=2 ΔT=100-10=90 C U=220 Δt=17*60=1020 c
КПД=0,86
КПД=(с*m*ΔТ)/(I*U*Δt)
I=(c*m*ΔT)/(КПД*U*Δt)=(4200*2*90)/(0.86*220*1020)=.............
R=U/I=...........



Calculation of Power
To determine the power consumed by the kettle, we can use the formula:Power (P) = Energy (E) / Time (t)
The energy consumed by the kettle can be calculated using the formula:
Energy (E) = Mass (m) * Specific Heat Capacity (c) * Temperature Change (ΔT)
Given that 2 liters of water are taken at 10°C and brought to boiling point (100°C), we can calculate the energy consumed.
Mass (m) = 2 kg (since 1 liter of water is approximately equal to 1 kg) Specific Heat Capacity (c) = 4.186 J/g°C (specific heat capacity of water) Temperature Change (ΔT) = 100°C - 10°C = 90°C
Substituting these values into the energy formula:
Energy (E) = 2 kg * 4.186 J/g°C * 90°C = 753.48 kJ
Now, we know that the kettle reaches boiling point in 17 minutes, which is equivalent to 17 * 60 = 1020 seconds.
Substituting the values of energy and time into the power formula:
Power (P) = 753.48 kJ / 1020 s = 0.738 kW
Efficiency of the Kettle
The efficiency (η) of the kettle is given as 86%. Efficiency is defined as the ratio of useful output energy to the input energy.Efficiency (η) = Useful Output Energy / Input Energy
In this case, the useful output energy is the energy used to heat the water, which we calculated as 753.48 kJ.
Substituting the values into the efficiency formula:
0.86 = Useful Output Energy / 753.48 kJ
Solving for the useful output energy:
Useful Output Energy = 0.86 * 753.48 kJ = 648.05 kJ
Determining the Resistance of the Heating Element
To determine the resistance of the heating element, we can use Ohm's Law:Resistance (R) = Voltage (V) / Current (I)
Given that the voltage is 220V, we need to calculate the current.
Power (P) = Voltage (V) * Current (I)
Substituting the values of power and voltage:
0.738 kW = 220V * Current (I)
Solving for the current:
Current (I) = 0.738 kW / 220V = 0.00335 A
Now, we can substitute the values of voltage and current into Ohm's Law to calculate the resistance:
Resistance (R) = 220V / 0.00335 A = 65,672.39 Ω
Therefore, the resistance of the heating element is approximately 65,672.39 ohms.
Please note that the search results provided did not contain relevant information for this specific calculation. The calculations were done based on the given information and general knowledge of physics principles.


Топ вопросов за вчера в категории Физика
Последние заданные вопросы в категории Физика
-
Математика
-
Литература
-
Алгебра
-
Русский язык
-
Геометрия
-
Английский язык
-
Химия
-
Физика
-
Биология
-
Другие предметы
-
История
-
Обществознание
-
Окружающий мир
-
География
-
Українська мова
-
Информатика
-
Українська література
-
Қазақ тiлi
-
Экономика
-
Музыка
-
Право
-
Беларуская мова
-
Французский язык
-
Немецкий язык
-
МХК
-
ОБЖ
-
Психология
-
Физкультура и спорт
-
Астрономия
-
Кыргыз тили
-
Оʻzbek tili