Question

Тепловой двигатель получает от нагревателя 600 дж теплоты из которых 200 дж отдаётся холодильнику . Какую работу совершает двигатель ? СРОЧНО

Answer 1

Дано Q1=600 Дж     Q2=200 Дж   A- ?

A=Q1-Q2=600-200=400 Дж

Answer 2

КПД=А*100%/Qн и КПД=(Qн-Qх)*100%/Qн
А=Qн-Qх

Answer 3

Calculation of Work Done by the Heat Engine

To calculate the work done by the heat engine, we need to consider the amount of heat received from the heater and the amount of heat rejected to the refrigerator.

Given: - Heat received from the heater: 600 J - Heat rejected to the refrigerator: 200 J

The work done by the heat engine can be calculated using the equation:

Work = Heat received - Heat rejected

Substituting the given values:

Work = 600 J - 200 J = 400 J

Therefore, the heat engine performs 400 J of work.