Question

Помогите пожалуйста Пуля массой 24 г, летящая с горизонтальной скоростью 600 м/с, попадает в мешок с песком массой 10 кг, висящий на длинной нити, и застревает в нем. Определить высоту, на которую поднимется мешок после удара.

Answer 1

Вроде бы получиться 0.25 гр, при условии что пуля застрянет в паралоне
E=m1*g*h=m2*v^2/2 т. к. длина нити не дана =>
m1=2m2*g*h / v^2
m1= 2 * 4*10*0.05/ 400^2

Answer 2

Calculation of the Height the Bag Will Rise After Impact

To determine the height to which the bag will rise after the impact, we can use the principle of conservation of momentum. The momentum before the impact is equal to the momentum after the impact.

The momentum of an object is given by the product of its mass and velocity. In this case, the bullet has a mass of 24 g (0.024 kg) and a horizontal velocity of 600 m/s. The bag has a mass of 10 kg and is initially at rest.

Before the impact, the momentum of the bullet is:

Momentum of the bullet before impact = mass of the bullet × velocity of the bullet

Momentum of the bullet before impact = 0.024 kg × 600 m/s

After the impact, the bullet becomes embedded in the bag, and both the bullet and the bag move together. Let's assume that the bag rises to a height 'h' after the impact.

The momentum of the bullet and the bag after the impact is:

Momentum of the bullet and bag after impact = (mass of the bullet + mass of the bag) × velocity of the bullet and bag

Momentum of the bullet and bag after impact = (0.024 kg + 10 kg) × 600 m/s

According to the principle of conservation of momentum, the momentum before the impact is equal to the momentum after the impact:

Momentum of the bullet before impact = Momentum of the bullet and bag after impact

Therefore, we can equate the two expressions for momentum and solve for the height 'h':

0.024 kg × 600 m/s = (0.024 kg + 10 kg) × 600 m/s

Simplifying the equation:

0.024 kg = 10.024 kg × h

Solving for 'h':

h = 0.024 kg / 10.024 kg

Calculating the value of 'h':

h ≈ 0.002394 m

Therefore, the bag will rise to a height of approximately 0.002394 meters (or 2.394 millimeters) after the impact.

Please note that this calculation assumes ideal conditions and neglects factors such as air resistance and the deformation of the bag and the bullet upon impact.