Question

Помогите пожалуйста даю 20 баллов Как изменится модуль силы взаимодействия двух точечных неподвижных положительных зарядов в воздухе , если оба заряда увеличить в 2 раза , а расстояние между ними увеличить в 6 раз

Answer 1

Fэ=k*q1*q1 и всё это разделить на расстояние в квадрате 

Answer 2

Changes in the Force of Interaction between Two Fixed Positive Charges in Air

When two point-like positive charges are placed in air, the force of interaction between them can be calculated using Coulomb's law. Coulomb's law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

If both charges are increased by a factor of 2 and the distance between them is increased by a factor of 6, we can determine how the force of interaction will change.

Let's denote the initial charge magnitude as q and the initial distance between the charges as r. After the changes, the new charge magnitude will be 2q and the new distance between the charges will be 6r.

According to Coulomb's law, the force of interaction between the charges can be calculated as:

F = k * (q1 * q2) / r^2

Where: - F is the force of interaction - k is the electrostatic constant (approximately equal to 9 x 10^9 Nm^2/C^2) - q1 and q2 are the magnitudes of the charges - r is the