Question

Какое ко-во теплоты выделяется при конденсации водяного пара массой 200г, имеющую температуру 100 градусов С, Удельная теплота парообразования воды 2300 кДж/ кг.

Answer 1

Q=-L*m=-2300*10^3*0,2=-46*10^4 Дж
Знак минус показывает, что энергия выделяется в окружающую среду.

Answer 2

Calculation of Heat Released during Condensation of Water Vapor

To calculate the amount of heat released during the condensation of water vapor, we can use the formula:

Q = m * L

Where: - Q is the heat released (in joules) - m is the mass of water vapor (in kilograms) - L is the specific latent heat of vaporization of water (in joules per kilogram)

In this case, we are given: - Mass of water vapor (m) = 200 grams = 0.2 kilograms - Specific latent heat of vaporization of water (L) = 2300 kJ/kg = 2300000 J/kg

Substituting these values into the formula, we get:

Q = 0.2 kg * 2300000 J/kg

Calculating this, we find that the heat released during the condensation of water vapor with a mass of 200 grams and a specific latent heat of vaporization of 2300 kJ/kg is:

Q = 460000 J

Therefore, 460000 joules of heat are released during the condensation of water vapor with a mass of 200 grams and a specific latent heat of vaporization of 2300 kJ/kg.