Question

В горизонтальное однородное электрическое поле помещен шарик массой 1г, подвешенный но тонкой шелковой нити. Шарику сообщен заряд 1мкКл. Определите значение напряженности поля, если нить отклонилась от вертикали на угол 60 градусов.

Answer 1

Находим проекции сил на оси:
T*sina=q*E(1)
T*cosa=m*g
T=m*g/cos (2)
Подставим 2 в 1
m*g*tga=q*E
E=m*g*tga/q=10^-3*10*1,73/10^-6=1,73*10^-4 В/м

Answer 2

Calculation of Electric Field Strength

To determine the value of the electric field strength in a horizontal homogeneous electric field, we can use the given information about the mass of the ball, the charge on the ball, and the angle of deflection of the silk thread.

Let's break down the problem step by step:

1. We are given that the mass of the ball is 1 gram, which is equivalent to 0.001 kilograms. 2. The charge on the ball is given as 1 microcoulomb, which is equivalent to 1 × 10^-6 coulombs. 3. The silk thread is deflected from the vertical by an angle of 60 degrees.

To find the electric field strength, we can use the equation:

Electric Field Strength (E) = (Force (F)) / (Charge (q))

The force acting on the ball is the gravitational force, which can be calculated using the equation:

Force (F) = (Mass (m)) × (Acceleration due to gravity (g))

The acceleration due to gravity is approximately 9.8 m/s^2.

Now, let's calculate the force acting on the ball:

Force (F) = (0.001 kg) × (9.8 m/s^2)

Calculating the force, we find:

Force (F) = 0.0098 N

Next, we can calculate the electric field strength:

Electric Field Strength (E) = (0.0098 N) / (1 × 10^-6 C)

Calculating the electric field strength, we find:

Electric Field Strength (E) = 9.8 × 10^3 N/C

Therefore, the value of the electric field strength in the given scenario is 9.8 × 10^3 N/C.

Please note that the search results did not provide specific information related to this particular problem. The solution is based on the principles of electrostatics and the given parameters.