Question

ОПределите жесткость пружины динамометра,если под действием силы 80 H она удлинилась на 5 см

Answer 1

 жесткость пружины k = F/x =80 / 0.05=1600 Н/м

Answer 2

Determining the Spring Constant of the Dynamometer

To determine the spring constant (k) of the dynamometer when a force of 80 H is applied and it elongates by 5 cm, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to its elongation.

Hooke's Law states that the force (F) exerted by a spring is directly proportional to its elongation (x), and it can be expressed as:

F = kx,

where: - F = force applied to the spring (in newtons, N), - k = spring constant (in newtons per meter, N/m), - x = elongation of the spring (in meters, m).

Calculation

Using the given values: - Force (F) = 80 H (or 80 N), - Elongation (x) = 5 cm = 0.05 m,

we can rearrange Hooke's Law to solve for the spring constant (k):

k = F / x

Substitute the given values: k = 80 N / 0.05 m

Result

k = 1600 N/m

Therefore, the spring constant of the dynamometer is 1600 N/m.