Question

Мотоцикл, трогаясь с места движется равноускорено. Его ускорение равно 2м/с 2. Какой путь он пройдет за 4-тую секунду ?

Answer 1

Надо сначала найти расстояние 2 секунды получаем 4:2м/с=2 метра потом мы 2*4=8 метров путь за 4 секунды

Answer 2

Calculation of the Distance Traveled by the Motorcycle

To calculate the distance traveled by the motorcycle in the fourth second, we need to use the equation of motion for uniformly accelerated motion:

\[s = ut + \frac{1}{2}at^2\]

Where: - s is the distance traveled - u is the initial velocity (which is 0 in this case since the motorcycle starts from rest) - a is the acceleration (given as 2 m/s^2) - t is the time (in this case, the fourth second)

Plugging in the values, we get:

\[s = 0 \cdot 4 + \frac{1}{2} \cdot 2 \cdot 4^2\]

Simplifying the equation:

\[s = 0 + 4 \cdot 4^2\]

\[s = 0 + 4 \cdot 16\]

\[s = 64\]

Therefore, the motorcycle will travel a distance of 64 meters in the fourth second.