Question

Протон влетает в однородноемагнитное поле , индукция которого равна 3,4∙10-2 Тл, перпендикулярно линиям индукции со скоростью 3,5·105 м/с. Определите радиус кривизны траектории протона

Answer 1

r=m*V/q*B    заряд и масса протона равны массе и заряду элктрона

r=9.1·10^-31кг*3.5·10^5м/с÷1.6·10^-19Кл*3.4·10^-21Тл=5,8·10^-4м

Answer 2

Calculation of the Radius of Curvature of the Proton's Trajectory

To determine the radius of curvature of the proton's trajectory, we need to consider the motion of a charged particle in a uniform magnetic field. The formula for the radius of curvature is given by:

r = (m*v) / (q*B)

Where: - r is the radius of curvature - m is the mass of the particle - v is the velocity of the particle - q is the charge of the particle - B is the magnetic field strength

In this case, we are given the following values: - The magnetic field strength (B) is 3.4 * 10^(-2) T (tesla) - The velocity (v) of the proton is 3.5 * 10^5 m/s

To calculate the radius of curvature, we need to know the mass and charge of the proton. The mass of a proton is approximately 1.67 * 10^(-27) kg, and the charge is equal to the elementary charge, which is approximately 1.6 * 10^(-19) C.

Substituting these values into the formula, we get:

r = (1.67 * 10^(-27) kg * 3.5 * 10^5 m/s) / (1.6 * 10^(-19) C * 3.4 * 10^(-2) T)

Calculating this expression gives us the radius of curvature of the proton's trajectory.

Let's perform the calculation.