Question

Баллон вместимостью 40 л содержит 1,98 кг углекислого газа . Баллон выдерживает давление не выше 30×10^5 Па. При какой температуре возникает опасность взрыва ?

Answer 1

PV=νRT
R=8,31
V=40л=40*10^-3м3=4*10^-2м3
ν=m/M
M(CO2)=12+32=44*10^-3 кг/моль
P=mRT/MV
30*10^5=1,98*8,31*T/44*10^-3*4*10^-2
5280=16,4538T
T=320,89K

Answer 2

Calculation of Temperature for Explosion Risk

To determine the temperature at which there is a risk of explosion, we need to use the ideal gas law, which states that the pressure, volume, and temperature of a gas are related by the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

Given: - Volume of the cylinder (V) = 40 L - Mass of carbon dioxide gas (m) = 1.98 kg - Molar mass of carbon dioxide (M) = 44.01 g/mol - Pressure limit of the cylinder (P) = 30 × 10^5 Pa

To find the number of moles of carbon dioxide gas, we can use the equation n = m/M, where n is the number of moles, m is the mass, and M is the molar mass.

Let's calculate the number of moles of carbon dioxide gas: n = m/M = 1.98 kg / 44.01 g/mol = 0.045 moles

Now, we can rearrange the ideal gas law equation to solve for temperature (T): T = PV / (nR)

The ideal gas constant (R) is 8.314 J/(mol·K).

Let's substitute the values into the equation and calculate the temperature:

T = (30 × 10^5 Pa) × (40 L) / (0.045 moles × 8.314 J/(mol·K))

Calculating this equation gives us the temperature in Kelvin.

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